Evaluate each of the following:
As sec(–θ) is sec(θ)
∴ sec = sec
The value of sec is 2.
Let sec–1(2) = y
⇒ sec y = 2
⇒ sec()
The range of principal value of sec–1is [0, π]–{}
And sec = 2
∴ The value of sec–1(sec) is .