Evaluate each of the following:

As sec(–θ) is sec(θ)


sec = sec


The value of sec is –√2 .


Let sec–1(–√2) = y


sec y = –√2


= – sec = √2


= sec


= sec


The range of principal value of sec–1is [0, π]–{}


and sec = –√2.


Therefore, the value of sec–1sec is .


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