Evaluate each of the following:

As we know cosec(–θ) = –cosecθ
∴ cosec
= –cosec![]()
–cosec
can be written as –cosec![]()
Also,
cosec(2π+θ) = cosecθ
∴ –cosec
= –cosec![]()
As we know –cosec(θ) = cosec(–θ)
∴ –cosec
= cosec![]()
Now the question becomes cosec–1(cosec
)
cosec–1(cosec x) = x
Provided x ϵ
–{0}
∴ we can write cosec–1(cosec
.