Evaluate each of the following:

As we know cosec(–θ) = –cosecθ


cosec = –cosec


–cosec can be written as –cosec


Also,


cosec(2π+θ) = cosecθ


–cosec = –cosec


As we know –cosec(θ) = cosec(–θ)


–cosec = cosec


Now the question becomes cosec–1(cosec)


cosec–1(cosec x) = x


Provided x ϵ –{0}


we can write cosec–1(cosec.


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