In Fig. 6.39, ABC and AMP are two righttriangles, right angled at B and Mrespectively. Prove that:
(i) Δ ABC ~ Δ AMP
(ii)
(i) In ΔABC and ΔAMP,
∠ABC = ∠AMP (Each 90°)
∠A = ∠A (Common)
∴ΔABC ΔAMP (By AA similarity)
(ii) (Corresponding sides of similar triangles are proportional)