Listen NCERT Audio Books to boost your productivity and retention power by 2X.
Evaluate each of the following:
The value of cot is √3.
∴ The question becomes cot–1(√3).
Let cot–1(√3) = y
⇒ cot y = √3
= cot = √3
The range of principal value of cot–1is (0, π)
and cot = √3
∴ The principal value of cot–1(cot) is .