Write each of the following in the simplest form:

Put x = sin2θ
And we know sin2θ +cos2θ = 1
By putting these in above equation, we get
= sin–1
= sin–1![]()
= sin–1![]()
= sin–1![]()
= sin–1(sin θ)
= θ
But θ =
sin–1x
∴ The given equation simplification to
sin–1x.