If AD and PM are medians of triangles ABC and PQR, respectively whereΔ ABC ~ Δ PQR, prove that

It is given that ΔABC is similar to ΔPQR

We know that the corresponding sides of similar triangles are in proportion



(i)


Also, A = P


B = Q


C = R (ii)


Since AD and PM are medians, they divide their opposite sides


BD = and,


QM = (iii)


From (i) and (iii), we get


(iv)


In ΔABD and ΔPQM,


B = Q [Using (ii)]


[Using (iv)]


ΔABD ΔPQM (By SAS similarity)



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