In Fig. 6.44, ABC and DBC are two triangles on thesame base BC. If AD intersects BC at O, show that
Let us draw two perpendiculars AP and DM on line BC
Area of a triangle =
Therefore,
=
In ΔAPO and ΔDMO,
∠APO = ∠DMO (Each = 90°)
∠AOP = ∠DOM (Vertically opposite angles)
∴ΔAPO ΔDMO (By AA similarity)