In Fig. 6.44, ABC and DBC are two triangles on thesame base BC. If AD intersects BC at O, show that

Let us draw two perpendiculars AP and DM on line BC

Area of a triangle =


Therefore,



=


In ΔAPO and ΔDMO,


APO = DMO (Each = 90°)


AOP = DOM (Vertically opposite angles)


ΔAPO ΔDMO (By AA similarity)




4