A tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of the top is 2.8 m, find the area of the canvas used for making the tent. Also, find the cost of the canvas of the tent at the rate of Rs 500 per m2. (Note that the base of the tent will not be covered with canvas)
Given:
Height (h) of the cylindrical part = 2.1 m
Diameter of the cylindrical part = 4 m
Radius of the cylindrical part = 2 m
Slant height (l) = 2.8 m
Area of canvas used = CSA of conical part + CSA of cylindrical part
= πrl + 2πrh
= π * 2 * 2.8 + 2π * 2 * 2.1
= 2π [2.8 + 2 * 2.1]
= 2π [2.8 + 4.2]
= 2 * 
* 7
= 44 m2
Cost of 1 m2 canvas = Rs 500
Cost of 44 m2 canvas = 44 × 500 = Rs22000