A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8g mass. (Use π = 3.14)
Given:
Height (h1) of larger cylinder = 220 cm
Radius (r1) of larger cylinder =
= 12 cm
Height (h2) of smaller cylinder = 60 cm
Radius (r2) of smaller cylinder = 8 cm
Total volume = Volume (Larger cylinder) + Volume (Smaller cylinder)
= πr12h1 + πr22h2
= π (12)2 * 220 + π (8)2 * 60
= π [144 * 220 + 64 * 60]
= 35520 * 3.14
= 111532.8 cm3
Mass of 1 cm3 iron = 8 g
Mass of 111532.8 cm3 iron = 111532.8 × 8
= 892262.4 g
= 892.262 kg
8