The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 2 more balls of the same kind for Rs 1300. Represent this situation algebraically and geometrically.
Let cost of one bat = Rs. X
Let cost of one ball = Rs. Y
According to the question,
= 
Dividing equation by 3.
=
=
Putting y = -1300 , 0 , 1300 we get,
X = 1300 – 2(-1300) = 1300+2600 = 3900
X = 1300 – 2(0) = 1300
X = 1300 – 2(1300) = 1300 – 2600 = -1300
X | 3900 | 1300 | -1300 |
Y | -1300 | 0 | 1300 |
She buys another bat and 2 more balls of the same kind for Rs.1300 (Given)
= 
=
Putting y = -1300 , 0 , 1300 we get,
X = 1300 – 2(-1300) = 1300+2600 = 3900
X = 1300 – 2(0) = 1300
X = 1300 – 2(1300) = 1300 – 2600 = -1300
X | 3900 | 1300 | -1300 |
Y | -1300 | 0 | 1300 |
Algebric representation:
3x+6y = 3900………………..(i)
X+2y= 1300…………………..(ii)
Graphical Representation for first equation:
Graphical Representation for second equation:
