Form the pair of linear equations in the following problems, and find their solutions graphically.
(i) 10 students of Class X took part in a Mathematics quiz. If the number of girls is 4 more than the number of boys, find the number of boys and girls who took part in the quiz.
(ii) 5 pencils and 7 pens together cost Rs 50, whereas 7 pencils and 5 pens together cost Rs 46. Find the cost of one pencil and that of one pen.
(i) Let number of boys = x
Let number of girls = y
According to the question,
=
=
Putting y = 0 , 5, 10 . we get,
X = 10 – 0 = 10
X = 10 – 5 = 5
X = 10 – 10 = 0
x | 10 | 5 | 0 |
y | 0 | 5 | 10 |
Number of girls is 4 more than number of boys …………Given
So,
Y = x + 4
Putting x = -4 ,0 , 4 we get,
Y = -4+4 = 0
Y= 0 + 4 = 4
Y = 4 + 4 = 8
x | -4 | 0 | 4 |
Y | 0 | 4 | 8 |
Graphical representation :
(ii) Let cost of one pencil = Rs. X
Let cost of one pen = Rs. Y
According to the question,
=
=
=
Putting value of y = 5 , 10 , 15 we get,
X =
X =
X =
x | 3 | -4 | -11 |
Y | 5 | 10 | 15 |
Now,
7 pencils and 5 pens together cost Rs. 46
7x + 5y = 46
= 5y = 46 – 7x
= y = 9.2 – 1.4x
Putting x = 0 , 2 , 4 we get,
Y= 9.2 – 1.4×0 = 9.2
Y = 9.2 – 1.4 × 2 = 9.2 – 2.8 = 6.4
Y = 9.2 – 1.4 × 4 = 9.2 – 5.6 = 3.6
x | 0 | 2 | 4 |
y | 9.2 | 6.4 | 3.6 |
Graphical Representation: