Draw a triangle ABC with side BC = 7 cm, B = 45°, A = 105°. Then, construct a triangle whose sides are times the corresponding sides of Δ ABC.

Steps of construction:

i. Now in order to make a triangle, draw a line segment BC = 7 cm.


ii. Now, construct an angle of 45o at point B and 30o at point C (because 45 + 30 + 105 = 180).


iii. Then, join the lines from points B and C to point A.


This gives us the required triangle ABC.



iv. Dividing the Base, construct a ray BX forming an acute angle from point B.


v. Plot 4 points on BX such that:


BB1 = B1B2 = B2B3 = B3B4.


vi. Join B3 to C.


vii. Now, draw a line from B4 parallel to B3C such that it meets line BC at C’.


viii. Draw A’C’ || AC.


Triangle A’BC’ is the required triangle.


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