ABCD is a cyclic quadrilateral (see Fig. 3.7). Find the angles of the cyclic quadrilateral.
We know that the sum of the measures of opposite angles in a cyclic quadrilateral is 180°. Therefore, ∠ A + ∠ C = 180
4y + 20 - 4x = 180 - 4x + 4y = 160
x - y = - 40 (i)
Also, ∠ B + ∠ D = 180 3y - 5 - 7x + 5 = 180 - 7x
+ 3y = 180 (ii)
Multiplying equation (i) by 3, we obtain 3x - 3y = - 120 (iii)
Adding equations (ii) and (iii), we obtain
- 7x + 3x = 180 - 120
- 4x = 60
x = -15
By using equation (i), we obtain x - y = - 40
-15 - y = - 40
y = -15 + 40 = 25
∠ A = 4y + 20 = 4(25) + 20 = 120°
∠ B = 3y - 5 = 3(25) - 5 = 70°
∠ C = - 4x = - 4(- 15) = 60°