In the following APs, find the missing terms in the boxes :

(i)


(ii)


(iii)


(iv)


(v)

(i) We know: In AP, middle term is average of the other two terms


Hence, middle term = (2 + 26)/2 = 28/2 = 14


Thus, above AP can be written as 2, 14, 26


(ii) The middle term between 13 and 3 will be;


(13 + 3)/2 = 16/2 = 8


Now, a4 – a3 = 3 – 8 = - 5


a3 – a2 = 8 – 13 = - 5


Thus, a2 – a1 = - 5


Or, 13 – a1 = - 5


Or, a1 = 13 + 5 = 18


Thus, above AP can be written as 18, 13, 8, 3


(iii) We have, a = 5 and a4 = 91/2


Now common difference:


a4 = a + 3d


= 5 +




d =


Hence, using d, 2nd term and 3rd term can be calculated as:


a2 = a + d


= 5 +


=


a3 = a + 2d


= 5 +


= 8


Therefore, the A.P. can be written as:


5,


(iv) Here, a = - 4 and a6 = 6


Common difference:


a6 = a + 5d


6 = -4 + 5d


5d = 6 + 4 = 10


d = 2


The second, third, fourth and fifth terms of this AP are:


a2 = a + d = - 4 + 2 = - 2


a3 = a + 2d = - 4 + 4 = 0


a4 = a + 3d = - 4 + 6 = 2


a5 = a + 4d = - 4 + 8 = 4


Thus, the given AP can be written as: - 4, - 2, 0, 2, 4, 6


Let us take 38 as the first term and – 22 as the 5th term


Using this, common difference can be calculated as follows:


a5 = a + 4d


= 38 + 4d


4d = - 22 – 38 = - 60


d = - 15


If 38 is the second term, then first term:


a = a2 – d = 38 + 15 = 53


Third, fourth and fifth terms ar:


a3 = a + 2d = 53 + 2(- 15) = 53 – 30 = 23


a4 = a + 3d = 53 – 45 = 8


a5 = a + 4d = 53 – 60 = - 7


So, the AP can be written as: 53, 38, 23, 8, - 7, - 22


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