Now we will multiply the two first matrices on LHS using the formula c_ij = a_i1b_1j + a_i2b_2j + … + a_inb_nj, we get

Again multiply these two LHS matrices, we get

⇒ 4 + 4x = 0 we will solve this linear equation, we get

⇒ 4x = – 4

This gives, x = – 1 is the required solution of the matrices.