If and x2 = – 1, then show that (A + B)2 = A2 + B2.

Given, and x2 = –1.


We need to prove (A + B)2 = A2 + B2.


Let us evaluate the LHS and the RHS one at a time.


To find the LHS, we will first calculate A + B.





We know (A + B)2 = (A + B)(A + B).






( x2 = –1)



To find the RHS, we will first calculate A2 and B2.


We know A2 = A × A.






( x2 = –1)


Similarly, we also have B2 = B × B.






Now, the RHS is A2 + B2.





Thus, (A + B)2 = A2 + B2.


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