Prove the following identities:
L.H.S =
As |A| = |A|T
So,
If any two rows or columns of the determinant are interchanged, then determinant changes its sign
Apply C1→C1 + C2 + C3
Taking (a + b + c) common from C1 we get,
Applying, R3→R3 – 2R1
= – (a + b + c)[(b – c)(a + b – 2c) – (c – a)(c + a – 2b)]
= 3abc – a3 – b3 – c3
As, L.H.S = R.H.S, hence proved.