Find the area of the triangle with vertices at the points:
(– 1, – 8), (– 2, – 3) and (3, 2)
Given: – Vertices of the triangle:
(– 1, – 8), (– 2, – 3) and (3, 2)
We know that,
If vertices of a triangle are (x1,y1), (x2,y2) and (x3,y3), then the area of the triangle is given by:
Now, substituting given value in above formula
Expanding along R1
sq.units
as area cannot be negative
Therefore, 15 sq.unit is the area
Thus area of triangle is 15 sq.units