Using determinants, find the equation of the line joining the points

(1, 2) and (3, 6)

Given: – (1, 2) and (3, 6) are collinear points


Tip: – For Three points to be collinear, the area of the triangle formed by these points will be zero


Now, we know that,


Vertices of a triangle are (x1,y1), (x2,y2) and (x3,y3), then the area of the triangle is given by:



Now,


Let, 3rd point be (x,y)


Substituting given value in above formula




Expanding along R1



[x(– 4) – y(– 2) + 1(0)] = 0


– 4x + 2y = 0


y = 2x


It’s the equation of line


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