Given: – Vertices of triangle are (k, 0), (4, 0) and (0, 2) and area of triangle is 4 sq. units

Tip: – If vertices of a triangle are (x₁,y₁), (x₂,y₂) and (x₃,y₃), then the area of the triangle is given by:

Now,

Substituting given value in above formula

⇒

Removing modulus

⇒

Expanding along R₁

⇒

⇒ [k(– 2) – 0(4) + 1(8 – 0)] = ±8

⇒ [ – 2k + 8] = ± 8

Taking + ve sign, we get

⇒ + 8 = – 2x + 8

⇒ – 2k = 0

⇒ k = 0

Taking – ve sign, we get

⇒ – 8 = – 2x + 8

⇒ – 2x = – 16

⇒ x = 8

Thus x = 0, 8