To prove whether f(x) is continuous at –1 & 1

If f(x) to be continuous at x = –1,we have to show, f(–1)^–=f(–1) ⁺ =f(–1)

LHL = f(–1)^– =

⇒ |(–2–0)| + |–0|

⇒ |–2|

∴|–x| = |x| = x

⇒ 2 ...(1)

RHL = f(–1) ^{+ =}

⇒ |(–2 + 0)| + |0|

∴|–x| = |x| = x

|–2|

2 ...(2)

From (1) & (2),we get f(–1)^–=f(–1) ⁺

Hence ,f(x) is continuous at x = –1

If f(x) to be continuous at x = 1,we have to show, f(1)^– =f(1) ⁺ =f(1)

LHL = f(1)^– =

⇒ |–0| + |2–0|

⇒ |2|

⇒ 2 ...(3)

RHL = f(1) ⁺ =

⇒ |0| + |2 + 0|

∴|–x| = |x| = x

⇒ |2|

⇒ 2 ...(4)

From (3) & (4),we get f(1)^–=f(1) ⁺

Hence ,f(x) is continuous at x = 1