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For what value of k is the following function continuous at x = 2?
Given:
For f(x) is continuous at x = 2 & f(2) = k
If f(x) to be continuous at x = 2,we have to show, f(2)–=f(2) + =f(2)
LHL = f(2)– =
⇒ (5–4×0)
⇒ 5 ...(1)
RHL = f(2) + =
⇒ (5 – 3 × 0)
⇒ 5 ...(2)
Since , f(x) is continuous at x = 2 & f(2) = k
k = 5