The houses of a row are numbered consecutively from 1 to 49. Show that there is a valueof x such that the sum of the numbers of the houses preceding the house numbered x isequal to the sum of the numbers of the houses following it. Find this value of x.

[Hint :]

In this question: a = 1, d = 1 and a49 = 49


According to question:


S(x-1) = S49 - Sx (i)


The sum of x terms can be calculated as:


Sx



= (x2+x)/2


Now, sum of 49 :


Sx



= 1225


Now,


After using the values of Sx-1, S49 and Sx in (i), we get;


Sx-1 = S49 -Sx


(x2 –x)/2 = 1225 - (x2 –x)/2


(x2 –x +x2+x)/2


(2x2)/2


x2 = 1225


x = 35


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