A tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle 30° with it. The distance between the foot of the tree to the point where the top touches the ground is 8 m. Find the height of the tree

Let BD be the tree.

Now, due to storm AD is broken and leans as AC.


AC is the broken part of the tree and AB is the part which is still upright.


Hence,


BC = 8 m


And,


∠ BCA=30o


Sum of AB and AC, which is equal to BD will give the height of the tree.


In Δ ABC:





AC =


Hence,





AB =


Now,


Height of tree= AB + AC


=


=


= 8


Hence, height of the tree is 8


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