Show that the points A (1, –2, –8), B (5, 0, –2) and C(11, 3, 7) are collinear, and find the ratio in which B divides AC.

We have been given the points A (1, –2, –8), B (5, 0, –2) and C (11, 3, 7).

We need to show that A, B and C are collinear.


Let us define the position vector.





So, in this case if we find a relation between , and , then we can easily show that A, B and C are collinear.


Therefore, is given by







And is given by







And is given by






Let us add and , we get






Thus, clearly A, B and C are collinear.


We need to find the ratio in which B divides AC.


Let the ratio at which B divides AC be λ : 1. Then, position vector of B is:



But the position vector of B is .


So, by comparing the position vectors of B, we can write





Solving these equations separately, we get



11λ + 1 = 5(λ + 1)


11λ + 1 = 5λ + 5


11λ – 5λ = 5 – 1


6λ = 4




The ratio at which B divides AC is λ : 1.


Since,


We can say



Solving it further, multiply the ratio by 3.



λ : 1 = 2 : 3


Thus, the ratio in which B divides AC is 2 : 3.


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