Find the inverse of each of the following matrices:
Now, |A| = – 10
Hence, A – 1 exists.
Cofactors of A are
C11 =
C12 = – 1
C21 = – 1
C22 = 0
Since, adj A =
(adj A) =
=
Now, A – 1 = .adj A
A – 1 = .
A – 1 =