Find the inverse of each of the following matrices:

Now, |A| = bc =


Hence, A – 1 exists.


Cofactors of A are


C11 =


C12 = – c


C21 = – b


C22 = a


Since, adj A =


(adj A) =


=


Now, A – 1 = .adj A


A – 1 = .


A – 1 =


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