Find the inverse of each of the following matrices:
Now, |A| = 2 + 15 = 17
Hence, A – 1 exists.
Cofactors of A are
C11 = 1
C12 = 3
C21 = – 5
C22 = 2
Since, adj A =
(adj A) =
=
Now, A – 1 = .adj A
A – 1 = .