|A| =

= 2(3 – 0) – 0 – 1(5)

= 6 – 5

= 1

Hence, A ^{– 1} exists

Cofactors of A are:

C₁₁ = 3 C₂₁ = – 1 C₃₁ = 1

C₁₂ = – 15 C₂₂ = 6 C₃₂ = – 5

C₁₃ = – 5 C₂₃ = – 2 C₃₃ = 2

adj A =

=

So, adj A =

Now, A ^{– 1} = .adj A

So, A ^{– 1} = .

Hence, A ^{– 1} =