Find the inverse of each of the following matrices.
|A| =
= 0 – 1(16 – 12) – 1( – 12 + 9)
= – 4 + 3
= – 1
Hence, A – 1 exists
Cofactors of A are:
C11 = 0 C21 = – 1 C31 = 1
C12 = – 4 C22 = 3 C32 = – 4
C13 = – 3 C23 = 3 C33 = – 4
adj A =
=
So, adj A =
Now, A – 1 = .adj A
So, A – 1 = .
Hence, A – 1 =