Find the inverse of each of the following matrices.

|A| =


= 0 – 1(16 – 12) – 1( – 12 + 9)


= – 4 + 3


= – 1


Hence, A – 1 exists


Cofactors of A are:


C11 = 0 C21 = – 1 C31 = 1


C12 = – 4 C22 = 3 C32 = – 4


C13 = – 3 C23 = 3 C33 = – 4


adj A =


=


So, adj A =


Now, A – 1 = .adj A


So, A – 1 = .


Hence, A – 1 =


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