Find the inverse of each of the following matrices.
|A| =
= 0 – 0 – 1( – 12 + 8)
= 4
Hence, A – 1 exists
Cofactors of A are:
C11 = – 8 C21 = 4 C31 = 4
C12 = 11 C22 = – 2 C32 = – 3
C13 = – 4 C23 = 0 C33 = 0
adj A =
=
So, adj A =
Now, A – 1 = .adj A
So, A – 1 = .
Hence, A – 1 =