Find the inverse of each of the following matrices.

|A| =


= 0 – 0 – 1( – 12 + 8)


= 4


Hence, A – 1 exists


Cofactors of A are:


C11 = – 8 C21 = 4 C31 = 4


C12 = 11 C22 = – 2 C32 = – 3


C13 = – 4 C23 = 0 C33 = 0


adj A =


=


So, adj A =


Now, A – 1 = .adj A


So, A – 1 = .


Hence, A – 1 =


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