Find the inverse of each of the following matrices.

|A| = – 0 + 0


= ()


= – 1


Hence, A – 1 exists


Cofactors of A are:


C11 = – 1 C21 = 0 C31 = 0


C12 = 0 C22 = C32 =


C13 = 0 C23 = C33 =


adj A =


=


So, adj A =


Now, A – 1 = .adj A


So, A – 1 = .


Hence, A – 1 =


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