Find the inverse of each of the following matrices.
|A| = – 0 + 0
= ()
= – 1
Hence, A – 1 exists
Cofactors of A are:
C11 = – 1 C21 = 0 C31 = 0
C12 = 0 C22 = C32 =
C13 = 0 C23 = C33 =
adj A =
=
So, adj A =
Now, A – 1 = .adj A
So, A – 1 = .
Hence, A – 1 =