The angles of elevation of the top of a tower from two points at a distance of 4 m and9 m from the base of the tower and in the same straight line with it are complementary. Prove that the height of the tower is 6 m
In this figure
∠ADB = θ and ∠ACB = 90°-θ
In Δ ABD;
In Δ ABC,
But we know that,
Therefore,
AB = 3*2
AB = 6 m
Hence proved.