The angles of elevation of the top of a tower from two points at a distance of 4 m and9 m from the base of the tower and in the same straight line with it are complementary. Prove that the height of the tower is 6 m

The angles of elevation of the top of a tower from two points at a distance of 4 m and9 m from the base of the tower and in the same straight line with it are complementary. Prove that the height of the tower is 6 m

In this figure

∠ADB = θ and ∠ACB = 90°-θ

In Δ ABD;

In Δ ABC,

But we know that,

Therefore,

AB = 3*2

AB = 6 m

Hence proved.

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