The angles of elevation of the top of a tower from two points at a distance of 4 m and9 m from the base of the tower and in the same straight line with it are complementary. Prove that the height of the tower is 6 m

In this figure

∠ADB = θ and ∠ACB = 90°-θ

In Δ ABD;




In Δ ABC,




But we know that,



Therefore,



AB = 3*2


AB = 6 m


Hence proved.

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