Let and . Show that

[G(β)] – 1 = G( – β)


|G(β)| = = 1


Cofactors of A are:


C11 = cos β C21 = sin α C31 = sin β


C12 = 0 C22 = 1 C32 = 0


C13 = sin β C23 = 0 C33 = cos β


Adj G(β) =


=


So, adj G(β) = …… (i)


Now, [G(β)] – 1 =


And, G( – β) =


=


Hence, [G (β)] – 1 = G( – β)


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