Show that 
satisfies the equation x2–12 x + 1 = 0. Thus, find A – 1
A = 
We have A2 – 12A + I = 0
A2 = 
= 
Now, A2 – 12A + 1 = 0
= 
= 
Hence, = 
Also, A2 – 12A + 1 = 0
= A – 12I + A – 1 = 0
= A – 1 = 12I – A
= 12
= 
Hence, A – 1 = 
23
Show that satisfies the equation x2–12 x + 1 = 0. Thus, find A – 1
A =
We have A2 – 12A + I = 0
A2 =
=
Now, A2 – 12A + 1 = 0
=
=
Hence, =
Also, A2 – 12A + 1 = 0
= A – 12I + A – 1 = 0
= A – 1 = 12I – A
= 12
=
Hence, A – 1 =