If , show that A – 1 = A3.

A =


|A| = 3 + 6 – 8 = 1


Cofactors of A are:


C11 = 1 C21 = – 1 C31 = 0


C12 = – 2 C22 = 3 C32 = – 4


C13 = – 2 C23 = 3 C33 = – 3


adj A =


=


So, adj A =


Now, A – 1 =


Also, A2 =


=


=


A3 = A2.A =


=


Hence, A – 1 = A3


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