Find the matrix X for which: .
Let A = B = C =
Then The given equations becomes as
AXB = C
= X = A – 1CB – 1
|A| = 35 – 14 = 21
|B| = – 1 + 2 = 1
A – 1 =
B – 1 =
= X = A – 1CB – 1 =
=
Hence, X =