Find the matrix X for which: .

Let A = B = C =


Then The given equations becomes as


AXB = C


= X = A – 1CB – 1


|A| = 35 – 14 = 21


|B| = – 1 + 2 = 1


A – 1 =


B – 1 =


= X = A – 1CB – 1 =


=


=


=


Hence, X =


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