A ^{– 1} = B =

|B| = 1(3 – 0) – 2( – 1 – 0) – 2(2 – 0)

= 3 + 2 – 4

|B| = 1

Now, B ^{– 1} =

Cofactors of B are:

C₁₁ = – 3 C₂₁ = 2 C₃₁ = 6

C₁₂ = 1 C₂₂ = 1 C₃₂ = 2

C₁₃ = 2 C₂₃ = 2 C₃₃ = 5

adj B =

=

So, adj B =

Now, B ^{– 1} =

(AB) ^{– 1 =} B ^{– 1} A ^{– 1}

=

Hence, =