Solve the following pair of linear equations by the substitution and cross-multiplication methods:
8x + 5y = 9
3x + 2y = 4
8x + 5y = 9........(i)
3x + 2y = 4........(ii)
From equation (ii), we get
....... (iii)
Substituting this value in equation (i), we obtain
32 - 16y + 15y = 27
-y = -5
Y = 5............. (iv)
Substituting this value in equation (ii), we obtain
3x + 10 = 4
x = -2
Hence, x = -2, y =5
Again, by cross-multiplication method, we obtain
8x + 5y - 9 =0
3x + 2y - 4 = 0
x = -2 and y = 5