Find in each of the following:
y3 – 3xy2 = x3 + 3x2 y
We are given with an equation y3 – 3xy2 = x3 + 3x2y, we have to find of it, so by differentiating the equation on both sides with respect to x, we get,
3y2 ‐ 3[y2(1) + 2xy ] = 3x2 + 3[2xy + x2]
Taking terms to left hand side and taking common , we get,
[3y2 ‐ 6xy ‐ 3x2] = 3x2 + 6xy + 3y2