If xy log (x + y) = 1, prove that

We are given with an equation xy log(x + y) = 1, we have to prove that by using the given equation we will first find the value of and we will put this in the equation we have to prove, so by differentiating the equation on both sides with respect to x, we get,


By using the triple product rule, which is, ,


(1)y log(x + y) + x log(x + y) + xy = 0


From the equation put log(x + y) =


= 0


= 0


= 0



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