If find at
We are given with an equation y = {logcosxsinx} {logsinxcosx} – 1 + sin – 1(), we have to find at
x = by using the given equation, so by differentiating the equation on both sides with respect to x, we get,
By using the properties of logarithms,
y = {logcosxsinx}2 + sin – 1()
y = {}2 + sin – 1()
= 2{}
= 2{}
= 2{}
Now putting the value of x = in the derivative solved above, we get,
(x = π/4) = 2{1} +
(x = π/4) = 2{1} +
(x = π/4) = 2{1} +
(x = π/4) = +