Find the vector equation of the line passing through the point (1, – 1, 2) and perpendicular to the plane 2x – y + 3z – 5 = 0.

Equation of line passing through and parallel to is given by ……(1)

Given that the line passes through (1, – 1,2) is


…… (2)


Since , line (1) is perpendicular to the plane 2x – y + 3z – 5 = 0, so normal to plane is parallel to the line.


In vector form,


is parallel to


So, as l is any scalar


Thus, the equation of required line,




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