Find the angle between the line and the plane 3x + 4y + z + 5 = 0.
We know that line is parallel to plane a2x + b2y + c2z + d2 = 0 if a1a2 + b1b2 + c1c2 = 0 is given by
……(1)
Now, given equation of line is
So, a1 = 3 , b1 = – 1 and c1 = 2
Equation of plane is 3x + 4y + z + 5 = 0
So, a2 = 3, b2 = 4, c2 = 1 and d2 = – 5
∴
⇒
⇒
⇒ sinθ = ⇒ θ = sin – 1(
∴ the angle between the plane and the line is sin – 1(