Find the value of k such that the line is perpendicular to the plane 3x – y – 2z = 7.
Here, given midline is perpendicular to plane 3x – y – 2z = 7.
We know that line is perpendicular to plane a2x + b2y + c2z + d2 = 0 if
So, normal vector of plane is parallel to line .
So, direction ratios of normal to plane are proportional to the direction ratios of line .
Here,
By cross multiplying the last two we have
– 2k = 4
⇒ k = – 2