Find the value of k such that the line is perpendicular to the plane 3x – y – 2z = 7.

Here, given midline is perpendicular to plane 3x – y – 2z = 7.

We know that line is perpendicular to plane a2x + b2y + c2z + d2 = 0 if


So, normal vector of plane is parallel to line .


So, direction ratios of normal to plane are proportional to the direction ratios of line .


Here,


By cross multiplying the last two we have


– 2k = 4


k = – 2


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