The equation of the given line is

…… (1)

The equation of the given plane is

…… (2)

Substituting the value of from equation (1) in equation (2), We obtain

(3 + 2) – (4 – 1) + (2 + 2) = 5

= 0

Substituting the value of equation (1), We obtain the equation of the line as

This means that the position vector of the point of intersection of the line and the

plane is

This shows that the point of intersection of the given plane and line is given by the coordinates, (2, – 1, 2). The point is (– 1, – 5, – 10) .

The distance d between the points, (2, – 1, 2) and (– 1, – 5, – 10) is

d =

d =

d = 13