Find the distance of the point P(– 1, – 5, – 10) from the point of intersection of the line joining the points A(2, – 1, 2) and B(5, 3, 4) with the plane x – y + z = 5 ?
Equation of line through the point A(2, – 1, 2) and B (5, 3, 4) is
⇒
⇒
Substituting these in the plane equation, We get
(3r + 2) – (4r – 1) + (2r + 2) = 5
⇒ r = 0
⇒ x = 2, y = – 1, z = 2
Distance of (2, – 1, 2) from (– 1, – 5, – 10) is
=
= 13