Show that the plane whose vector equation is contains the line whose vector equation is
we know that plane contains the line
if
Given, equation of plane and equation of line
So
d = 3
= (2)(1) + (1)(2) + (4)(– 1)
= 2 + 2 – 4
= (1)(1) + (1)(2) + (0)(– 1)
= 1 + 2 – 0
= 3
= d
Since, and
So, Given line is on the given plane.
Hence, Proved.