Show that the plane whose vector equation is contains the line whose vector equation is

we know that plane contains the line if



Given, equation of plane and equation of line


So


d = 3



= (2)(1) + (1)(2) + (4)(– 1)


= 2 + 2 – 4




= (1)(1) + (1)(2) + (0)(– 1)


= 1 + 2 – 0


= 3


= d


Since, and


So, Given line is on the given plane.


Hence, Proved.


6