Find the derivative of the function f(x) given by
f(x) = (1 + x)(1 + x2)(1 + x4)(1 + x8) and hence find f’(1)
Here,
f(x) = (1 + x)(1 + x2)(1 + x4)(1 + x8)
f(1) = (2)(2)(2)(2) = 16
Taking log on both sides we get,
Log (f (x)) = log (1 + x) + log (1 + x2) + log (1 + x4) + log(1 + x8)
Differentiating it with respect to x we get,
F’(1) = 120