Find the derivative of the function f(x) given by

f(x) = (1 + x)(1 + x2)(1 + x4)(1 + x8) and hence find f’(1)

Here,


f(x) = (1 + x)(1 + x2)(1 + x4)(1 + x8)


f(1) = (2)(2)(2)(2) = 16


Taking log on both sides we get,


Log (f (x)) = log (1 + x) + log (1 + x2) + log (1 + x4) + log(1 + x8)


Differentiating it with respect to x we get,







F’(1) = 120


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